Axiom Of Choice

This non-implication, Form 369 \( \not \Rightarrow \) Form 61, whose code is 4, is constructed around a proven non-implication as follows:

This non-implication was constructed without the use of this first code 2/1 implication.
A proven non-implication whose code is 3. In this case, it's Code 3: 946, Form 369 \( \not \Rightarrow \) Form 93 whose summary information is:

Hypothesis Statement

Form 369 <p> If \(\Bbb R\) is partitioned into two sets, at least one of them has cardinality \(2^{\aleph_0}\). </p>

Conclusion Statement

Form 93 <p> There is a non-measurable subset of \({\Bbb R}\). </p>
An (optional) implication of code 1 or code 2 is given. In this case, it's Code 2: 4308, whose string of implications is: 61 \(\Rightarrow\) 88 \(\Rightarrow\) 93

Hypothesis	Statement
Form 369	<p> If \(\Bbb R\) is partitioned into two sets, at least one of them has cardinality \(2^{\aleph_0}\). </p>

Conclusion	Statement
Form 93	<p> There is a non-measurable subset of \({\Bbb R}\). </p>

The conclusion Form 369 \( \not \Rightarrow \) Form 61 then follows.

Finally, the
List of models where hypothesis is true and the conclusion is false:

Name	Statement
\(\cal M5(\aleph)\) Solovay's Model	An inaccessible cardinal \(\aleph\) is collapsed to \(\aleph_1\) in the outer model and then \(\cal M5(\aleph)\) is the smallest model containing the ordinals and \(\Bbb R\)