Form equivalence class Howard-Rubin Number: 0
Statement:
For all cardinals \(m\) and \(n\), if \(2m=2n\),then \(m=n\). (Brought to our attention by W. Felscher.)
Howard-Rubin number: 0 AR
Citations (articles):
Sierpiński [1922]
Sur l''egalit'e 2m=2n pur les nombres cardinaux
Connections (notes):
References (books):
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