Statement:

Linking Axiom for Boolean Algebras: Every Boolean algebra has a maximal linked system. (\(L\subseteq B\) is linked if \(a\wedge b\neq 0\) for all \(a\) and \(b \in L\).)

Howard_Rubin_Number: 201

Parameter(s): This form does not depend on parameters

This form's transferability is: Unknown

This form's negation transferability is: Negation Transferable

Article Citations:
Schrijver-1978: The dependence of some logical axioms on disjoint transversals and linked systems

Book references

Note connections:

The following forms are listed as conclusions of this form class in rfb1: 88,

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Complete List of Equivalent Forms

Howard-Rubin Number Statement References
201 A

Strong Linking Axiom for Boolean Algebras: Each linked system in a Boolean algebra is contained in some maximal linked system. (If \(B\) is a Boolean algebra, \(L\subseteq B\) is linked if \(a\wedge b\neq 0\) for all \(a\) and \(b\in L\).)

Schrijver [1978]

201 B

Disjoint Transversal axiom (2,2): If \(X\) is a set and \({\cal U}\) and \({\cal V}\) are subsets of \(\{ y\subseteq X : |y|\le 2\}\) and if for each two finite subsets \({\cal U}_{0}\subseteq {\cal U}\) and \({\cal V}_{0} \subseteq {\cal V}\) there are transversals \(Y_{1}\) and \(Y_{2}\) for \({\cal U}_{0}\) and \({\cal V}_{0}\) respectively such that \(Y_{1} \cap Y_{2} = \emptyset\), then there are disjoint transversals \(X_{1}\) and \(X_{2}\) for \({\cal U}\) and \({\cal V}\) respectively. (\(Y\subseteq X\) is a transversal for \({\cal U}\) if for all \(y\in \cal U\), \(y\cap Y \ne\emptyset\).)

Schrijver [1978]