Statement:
For all Dedekind finite cardinals \(p\) and \(q\), if \(p^{2} = q^{2}\) then \(p = q\). Jech [1973b], p 162 prob 11.12.
Howard_Rubin_Number: 102
Parameter(s): This form does not depend on parameters
This form's transferability is: Unknown
This form's negation transferability is: Negation Transferable
Article Citations:
Book references
The Axiom of Choice, Jech, T., 1973b
Note connections:
Note 94
Relationships between the different definitions of finite